-2.75x^2+450x-3000=0

Solution for -2.75x^2+450x-3000=0 equation:

-2.75x^2+450x-3000=0

a = -2.75; b = 450; c = -3000;
Δ = b2-4ac
Δ = 4502-4·(-2.75)·(-3000)
Δ = 169500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{169500}=\sqrt{100*1695}=\sqrt{100}*\sqrt{1695}=10\sqrt{1695}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(450)-10\sqrt{1695}}{2*-2.75}=\frac{-450-10\sqrt{1695}}{-5.5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(450)+10\sqrt{1695}}{2*-2.75}=\frac{-450+10\sqrt{1695}}{-5.5}
$